Question

The three vertices of 11⁸ ABCD are A(1,-2), B(3,6) and C(5,10). Find the coordinates of tourth vertes D​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$given -$

Three vertices of 11^8 ABCD are

A(1,2)

B(3,6)

C(5,10)

$to \: find -$

The coordinates of fourth vertice D

$solution -$

Let the coordinates of the fourth vertex be (x,y)

We know that midpoint of line segment joining the points (x1,y1) and (x2,y2) is

(x1 + x2/2,y1 + y2/2).

Midpoint of AC = (1 + 5/2,-2+10/2)

= (3,4)

Midpoint of BD = (3 + x/2,6+y/2).

Now,

Midpoint of BD = Midpoint of AC.

(3 + x/2,6 + y/2) = (3,4)

3 + x/2 = 3, 6 + y/2 = 4

3 + x = 6, 6 + y = 8

x = 6 - 3,y = 8 - 6

x = 3, y = 2.

Therefore the fourth vertex is D(3,2).

$thank \: you$

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