Question

The three vertices of a parallelogram ABCD are A(3,-4),B(-1,-3)AND C(-6,2).Find the coordinates of vertex DFind the area of ABCD

Answer 1

This is the first part..



2nd part:-
(-1+a)/2, ( (-3)+b)/2
As Mid pt of AC =MID PT. OF BD
SO, -3/2=(-1+a)/2
-6=2(-1+a)
-6=-2+2a
-4=2a
-2=a

-1=(-3+b)/2
-2=-3+b
-2+3=b
1=b
vertices of D= (-2,1)

Answer 2

area = base × altitude.
( you may solve )
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