the three vertices of a parallelogram ABCD,taken in order, are A(1,-2),B(3,6)and C(5,10).find the coordinates of the fourth vertex D.
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Answered by
5
m(3,4)midpoint
d(3,2)
d(3,2)
sanathkumar170p2ltuv:
midpoint doesnt work on this
they asked the distance
not distance
coordinates
we can find the coordinated by applying the distance formula and by equating
Answered by
11
in this question
draw a diagonal ,
WKT, diagonals of a parallelogram are equal
i.e , ad = bc ,
apply distance formula
(x^2-x^1)^2 +(y^2-y^1)^2 and you will get the answer by using this formula
(2^2 +4^2) = (x-1)^2 +(y-(-2))^2
hope this helps
draw a diagonal ,
WKT, diagonals of a parallelogram are equal
i.e , ad = bc ,
apply distance formula
(x^2-x^1)^2 +(y^2-y^1)^2 and you will get the answer by using this formula
(2^2 +4^2) = (x-1)^2 +(y-(-2))^2
hope this helps
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