Question

The three vessels shown in figure have same base area. Equal volumes of a liquid are poured in the three vessels. The force on the base will be
(a) maximum in vessel A
(b) maximum in vessel B
(c) maximum in vessel C
(d) equal in all the vessels
Figure

Answer 1

Answer:

The three vessels shown in figure have same base area. Equal volumes of a liquid are poured in the three vessels. The force on the base will be

(a) maximum in vessel A✔

(b) maximum in vessel B

(c) maximum in vessel C

(d) equal in all the vessels

Figure

Answer 2

The force on the base will be equal in all the vessels.

Explanation:

1. Here volume of liquid is same for all three vessel.

2. Base area is also same for all three vessel, which is given.

3. Let

   base area of vessel A, vessel B, vessel C

  $A_{A}=A_{B}=A_{C}=A$

4. Volume(V) of liquid in all container is same.

   $V=H_{A}\times A_{A}=H_{B}\times A_{B}=H_{C}\times A_{C}$

  So $H_{A}=H_{B}=H_{C}=H$

5. Now Force at base of vessel A, vessel B, vessel C.

   $F_{A}=\rho \times g\times H_{A}\times A_{A}$    ...1)

   $F_{B}=\rho \times g\times H_{B}\times A_{B}$    ...2)

   $F_{C}=\rho \times g\times H_{C}\times A_{C}$    ...3)

6. From equation 1 , 2 and 3

  it is clear that for same value of density of liquid. Force in all three vessel is same.

7. So

  $F_{A}=F_{B}=F_{C}=F$