The threshold frequency for a ametel is v when light of frequency v=2v is incident on it the maximum velocity of the photoelectrons is 4
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here is your answer mate
The Einstein's equation for photoelectric effect is given by , KE=h\nu-h\nu_0KE=hν−hν
0
where KE=KE=maximum kinetic energy of electron, h=h= Planck's constant , \nu_0=ν
0
= threshold frequency and \nu=ν= frequency of incident light .
Also KE=\dfrac{1}{2}mv^2KE=
2
1
mv
2
where v=v= maximum velocity of electron.
In first case, \dfrac{1}{2}mv_1^2=h(2\nu_0)-h\nu_0=h\nu_0 ....(1)
2
1
mv
1
2
=h(2ν
0
)−hν
0
=hν
0
....(1) and
In second case, \dfrac{1}{2}mv_2^2=h(5\nu_0)-h\nu_0=4h\nu_0 ....(2)
2
1
mv
2
2
=h(5ν
0
)−hν
0
=4hν
0
....(2)
From (1) and (2), \dfrac{1}{2}mv_2^2=4\times \dfrac{1}{2}mv_1^2
2
1
mv
2
2
=4×
2
1
mv
1
2
or v_2=2v_1=2\times (4\times 10^6)=8\times 10^6 m/sv
2
=2v
1
=2×(4×106)=8×10
6
m/s
hope it helps
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