Question

The threshold frequency of a metal is 1 x 10¹5 Hz. The ratio of maximum kinetic energies of the photoelectrons when the metal is irradiated with radiations of frequencies 1.5x 10¹5 and 2x10¹5 Hz respectively would be​

Answer 1

Answer:

Correct option is

E

1×10

14

s

−1

Absorbed energy=threshold energy+KE

nv=nv

0

+KE

∴nv

0

=nv−KE

6.26×10

−34

×v

0

=6.26×10

−34

×2×10

14

−6.63×10

−20

∴v

0

=9.999×10

13

≃1×10

14

s

−1