The threshold frequency of a metal is 7*10^14 s^-1. Calculate the kinetic energy of the electrons emitted when radiations of frequency 10^15 Hz falls on it.
Answers
Answered by
13
K.E = h(f - f₀)
K.E = 6.626 × 10⁻³⁴ × (10¹⁵ - 7×10¹⁴)
K.E = 1.9878 × 10⁻¹⁹ J
K.E = 6.626 × 10⁻³⁴ × (10¹⁵ - 7×10¹⁴)
K.E = 1.9878 × 10⁻¹⁹ J
JunaidMirza:
Please mark it as Brainliest :)
How do you do that? I joined only yesterday evening!
Click “Mark as Brainliest” above my name.
I don't see it.
Thanks :)
Similar questions