Chemistry, asked by ishitamaggu, 9 months ago

The threshold wavelength for ejection of electron from metal is 310nm photon
The kinetic energy of emitted photo electrons is 36 x 10-20J. Then
frequency of incident light is.
Photoel
1) 1.5 x 1015 Hz
2) 2.5 1018 Hz
4) 2.5 x 1012
3) 1 x 1022 Hz

Answers

Answered by nagathegenius
4

Answer:

Explanation:

use the formula

hv-hv0=ke

where v0 is threshold frequency

take h common and equation as h(v-v0)=36*10^-20

v-v0=5.39*10^14

v=5.39*10^14+310nm

=5.39*10^14+3.1*10^-7

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