The threshold wavelength of tungsten
is 2.76 * 10^-5 cm. (a) Explain why no
photoelectrons are emitted when the
wavelength is more than 2.76 x 10^-5 cm
(b) What will be the maximum kinetic
energy of electrons ejected in each of the
following cases (1) if ultraviolet radiation
of wavelength - 1.80 - 10^-5 cm and
(ii) radiation of frequency 4x10 Hz is
made incident on the tungsten surface.
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The photoelectric threshold wavelength of tungsten toppr.com
Phototelectric law, KE = hc/λ - W = hc/λ - hc/λ∘ where, W = hc/λ∘ and λ∘ is threshold wavelength KE = hc ( 1/λ - 1λ∘ ) = 6.6 × 10-34
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