The threshout Frequency to bor a metal is 4,0 x 10145 - Calculate the kinetic energ of an electron emited when a radiation ergy of frequency r = 4.5 * 10145-1 hit's the
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The threshold frequency v
0
for a metal is 7.0×10
14
s
−1
. Calculate the kinetic energy of an electron emitted when radiation of frequency v=1.0×10
15
s
−1
hits the metal.
Hard
Solution
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Given that,
v
o
=7.0×10
14
s
−1
v=1.0×10
15
s
−1
As we know, hv=hv
0
+
2
1
mv
2
i.e. h(v−v
0
)=K.E.
∴K.E.=(6.626×10
−34
)×(1.0×10
15
−7.0×10
14
)=6.626×10
−34
×10
14
(10−7)
∴K.E=19.878×10
−20
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