English, asked by aditya541677, 5 days ago

The threshout Frequency to bor a metal is 4,0 x 10145 - Calculate the kinetic energ of an electron emited when a radiation ergy of frequency r = 4.5 * 10145-1 hit's the









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Answered by namdeoshikhu777
1

Answer:

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Class 11

>>Chemistry

>>Structure of Atom

>>Development Leading to Bohr's Model of Atom

>>The threshold frequency v0 ...

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The threshold frequency v

0

for a metal is 7.0×10

14

s

−1

. Calculate the kinetic energy of an electron emitted when radiation of frequency v=1.0×10

15

s

−1

hits the metal.

Hard

Solution

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Verified by Toppr

Given that,

v

o

=7.0×10

14

s

−1

v=1.0×10

15

s

−1

As we know, hv=hv

0

+

2

1

mv

2

i.e. h(v−v

0

)=K.E.

∴K.E.=(6.626×10

−34

)×(1.0×10

15

−7.0×10

14

)=6.626×10

−34

×10

14

(10−7)

∴K.E=19.878×10

−20

J

Answered by XxitzMichAditixX
2

Answer:-

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