The time a passenger train takes to cross another freight train running in same direction is twice when the passenger train crosses the freight train running in opposite direction. what is the ratio of their speeds?
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Let the speeds of 2 trains be x & y
Let distance travelled in crossing be d
t1 (same direction) = d/ (x-y)
t2 (opp direction) = d/ (x+y)
t1/ t2 = 2
[d/ (x-y)] / [d/ (x+y)] = 2
(x+y) / (x-y) = 2
x + y = 2x - 2y
3y = x
x/y = 3
Ratio of speeds of trains = 3:1
Let distance travelled in crossing be d
t1 (same direction) = d/ (x-y)
t2 (opp direction) = d/ (x+y)
t1/ t2 = 2
[d/ (x-y)] / [d/ (x+y)] = 2
(x+y) / (x-y) = 2
x + y = 2x - 2y
3y = x
x/y = 3
Ratio of speeds of trains = 3:1
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