Question

The time in which a tunning fork of
frequency 256 Hz completes 32 vibrations is
(1) 8 seconds. (2) 0.8 seconds.
(3) 1/8 seconds. (4) 0.08 seconds.​

Answer 1

Answer:

Frequency is given as f=256 Hz

Time period of tuning fork T=

f

1

=

256

1

As T is the time in which tuning fork will complete one vibration.

So, 32 T is the time in which fork will complete 32 vibrations.

∴ Time elapsed during 32 vibration t=32T=32×

256

1

=

8

1

sec

Distance traveled by sound during this time d=Vt =344×

8

1

⟹ d=43 m

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Answer 2

Answer:

(3) 1/8

Explanation:

256/1= 32/x

1/x= 256/32

x= 1/8