The time of 20 vibrations of a simple pendulum recorded by stopwatch accurate upto 1/10 of a second is 38.8. The time period is given by:
Answers
Answered by
1
Explanation:
20 vibration in 3.88 second
frequency=number of vibrations/ time
or ,time =number of vibrations/frequency
or,time=20÷5.15
or,time =3.88
The time period is3.88 s
Similar questions