Question

The time of flight for any projectile is 200sec and it's horizontal range is 400m.what is it's horizontal component of velocity

Answer 1

Answer:

time of flight formula = 2u sinθ / g

Horizontal Range formula = u^2 sin2θ / g

$\frac{r}{t} = \: \frac{ \frac{u {}^{2}2sin \alpha \: cos \alpha }{g} }{ \frac{2usin \alpha }{g} }$

400 / 200 = u cos α

2 m/s is horizontal velocity