Question

The time of flight of a projectile is 10 seconds. Its range on a horizontal plane is
100m. Calculate the angle of projection and the velocity of projection.

Answer 1

Answer:

50.99 m/s

Explanation:

Given problem:

The time of flight of a projectile is 10 seconds. Its range on a horizontal plane is  100m. Calculate the angle of projection and the velocity of projection.

Solution:

Since T = 10 s

And R = 100m

But, T = 2usinθ/g = 10

=> sinθ = 50/u         { g = 10 m/s2}

And, R = u2sin2 θ /g =100

=> u22sin θ cos θ /g = 100

=>cos  θ = 10/u

Since,  sinθ /cos  θ = tan θ

Therefore, 50/u x u/10 = tan θ

tan θ = 5

θ = 78.690

So u = 50/sin(78.69) = 50.99 m/s