Question

the time of flight of an object projected with speed 20m/s at an angle 40 degrees with the horizontal is??

Answer 1

Time of flight= 2v sin theta/g
= 2×20× sin40/9.8
=2×20×0.64279/9.8
=2.62sec

hope this helps you

Answer 2

Answer:

Time of flight, T = 2.62 seconds

Explanation:

Given that,

Speed of the object, v = 20 m/s

Angle with the horizontal, $\theta=40^{\circ}$

The time of flight of a projectile is given by :

$T=\dfrac{2v\ sin\theta}{g}$

g is the acceleration due to gravity

$T=\dfrac{2(20)\ sin(40)}{9.8}$

T = 2.62 seconds

So, the time of flight on an object is 2.62 seconds. Hence, this is the required solution.