Question

The time of oscillation t of a pendulum is given by t =2π√l/g Determine the approximate percentage error in t when L has a positive error of 0.2% and g has a negative error 0.1%

Answer 1

Answer:

0.2%

Step-by-step explanation:

∆t/t=%error in time

∆t/t=∆l/2l-∆g/g

∆t/t=0.5*0.2-(-0.1)

∆t/t=0.1+0.1

∆t/t=0.2%