Question

The time of reverberation of a room-A is one second. What will be the time(in seconds)of reverberation of a room, having all the dimensions double of those of room A?​

Answer 1

Answer:

2sec

Explanation:T1/T2=(v1/v2)(s2/s1)

S =surface area

V =volume

Edge length = a

Answer 2

Given that,

The time of reverberation of a room-A is one second.

To find,

The time of reverberation of a room having all the dimensions double of those of room A.

Solution,

The time of reverberation of a room is given by :

$T\propto \dfrac{V}{S}$

V is volume of room

S is total surface area of room

We can write as :

$\dfrac{T_1}{T_2}= \dfrac{V_1}{V_2}\times \dfrac{S_2}{S_1}$

If all the dimensions is doubled, then,

$\dfrac{T_1}{T_2}= \dfrac{V}{8V}\times \dfrac{4S}{S}\\\\\dfrac{T_1}{T_2}=\dfrac{1}{2}$

Here, T₁ = 1 s

$T_2=2\ s$

So, if all the dimension of the room is doubled, then time of reverberation of a room gets doubled.

Learn more,

Reverberation

https://brainly.in/question/4647550