Question

The time period if interest on rupees 1600 is rupees is rupees 432 at 6% per annum is​

Answer 1

Required Answer:-

GiveN:

• Principal = Rs. 1600
• Rate of interest = 6% per annum
• Simple Interest = Rs. 432

We have to FinD:

• The time period ?

Step-by-step Explanation:

We know the formula for finding SI:

• Simple Interest (SI) = P × T × R / 100

Where symbols have their usual meaning. Now just putting the values of SI, P and R:

➻ 432 = 1600 × 6 × T / 100

➻ T = 432 × 100 / 1600 × 6

➻ T = 432 / 16 × 6

➻ T = 4.5 years

Hence:

The time period of the simple interest is:

$\huge{ \boxed{ \sf{ \purple{4.5 \: years}}}}$

Answer 2

Required Solution:

Given:

• Principal = Rs. 1600
• Interest = Rs. 432
• Rate = 6%

To Find:

• Time period

Let The Time period be T,

The Formula Of Finding Simple Interest:

$\rm \: SI = \large \frac{P \times R \times T}{100}$

$\\ \tt \: 432 = \large \: \frac{1600 \times 6 \times t}{100}$

$\\ \sf \: T = \large \frac{432 \times 100}{1600 \times 6}$

$\\ \sf \: T = \large \: \frac{76 \times 100}{1600}$

$\\ \sf \: T = \sf \: \large \:\frac{76}{16} = 4.5$

$\\ \large \: \therefore \rm \: The \: Time \: period \: is \: 4.5 \: years$

• Amount = P + I = Rs. 1600 + Rs. 432 = Rs. 2032