The time period of a mercury is 88 days then find the radius of mercury?
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Let us assume masses of both the planet is same As per Kepler's lawT² α r³T² = k × r³
Rp/Rm = (Tp/ Tm)∧2/3
Rp = Rm (Tp/ Tm)∧2/3
put the values in the equation
Rp = (5.8 × 10∧10) (55/ 85)∧2/3
= 4.24 × 10∧10 days
radius of circuit is 4.24 × 10∧10 days
Let us assume masses of both the planet is same As per Kepler's lawT² α r³T² = k × r³
Rp/Rm = (Tp/ Tm)∧2/3
Rp = Rm (Tp/ Tm)∧2/3
put the values in the equation
Rp = (5.8 × 10∧10) (55/ 85)∧2/3
= 4.24 × 10∧10 days
radius of circuit is 4.24 × 10∧10 days
Bonimachyy:
after T sqr what is i?
it*
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It's proximity to the Sun also means that it orbits the planet quite rapidly. To break it down, Mercury takes roughly 88 Earth days to complete a single orbit around the Sun. Between this rapid orbital period and its slowrotational period, a single year on Mercury is actually shorter than a single day
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