Physics, asked by johnread9527, 1 year ago

The time period of a particle in simple harmonic motion is equal to the smallest time between the particle acquiring a particular velocity →v. The value of v is
(a) vmax
(b) 0
(c) between 0 and vmax
(d) between 0 and −vmax

Answers

Answered by vignesh320
0

Answer:

b o dvrbtetbebgbf fe eg g gndh ryb

Answered by shilpa85475
1

The time period of a particle in simple harmonic motion is equal to the smallest time between the particle acquiring a particular velocity →v. The value of v is   V_m_a_x.

Explanation:

  • The particle has the time period in simple harmonic motion, and this is defined as the time consumed for oscillation completion.  
  • Velocity is nothing but the direction as well as the magnitude, and it is a vector.
  • At the mean position, the maximum velocity acquired after a single time period by the particle at the same position.
  • Between one extreme and other extreme position, other velocities occur twice. So, the answer (a) is true and others are false.
Similar questions