Question

The time period of a pendulum is 4 sec. When it is placed in a lift accelerating up with 3 g then its time period will be :

Answer 1

it should be the answer

Answer 2

Answer:

The time length of the pendulum when it is positioned in a elevate accelerating up with three g will be about 1.14 instances the rectangular root of its authentic time period.

Explanation:

The time duration of a pendulum is given by:

                        T = 2π √(L/g)

where T is the time period, L is the size of the pendulum, and g is the acceleration due to gravity.

When the pendulum is positioned in a raise accelerating up with three g, the superb acceleration skilled through the pendulum is:

                            a_eff = g + a

where a is the acceleration of the lift.

So, the new time length of the pendulum can be calculated as:

T_new = 2π √(L/a_eff)

T_new = 2π √(L/(g + a))

T_new = 2π √(L/(9.8 m/s^2 + 3g))

T_new = 2π √(L/(9.8 m/s^2 + three * 9.8 m/s^2))

T_new = 2π √(L/29.4 m/s^2)

T_new = 2π √(L/29.4) seconds

T_new = (2π/√29.4) √L seconds

T_new = 1.14 √L seconds (approx.)

Therefore, the time length of the pendulum when it is positioned in a elevate accelerating up with three g will be about 1.14 instances the rectangular root of its authentic time period.

For more such related questions : https://brainly.in/question/9805789

#SPJ3