The time period of a satellite of earth is 5h . if the separation between the earth and the satellite is increased to 4 times the previous value ,the new time period will become [AIEEE 2003]
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Explanation:- According to kepler's law
- T² ∝r³
- ⟹ 5² ∝ T³ _____ (i)
- and ,(T')² ∝ (5r)³
From Equation (i) and (ii) , we have
25 /(T')² = r³/,64r³
⟹ T ' = √64* 25
⟹ T' = √1600 = 40hour
The new time period will be 40h
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