The time period of a seconds pendulum is 2s. What is the length of the pendulum?
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Answer:
T=2π√Lg
T = 2 π L g let here g(gravitational)
=
T=2s 10m/s
2 = 2 * 3.14 * L * 10
2 = 68L
L = 2/68
L = 1/34
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