Question

The time period of a simple pendulum inside a stationary lift is T. If the lift start moving upwards with an acceleration of g/3, what will be the time period?

Answer 1

Answer:

$\sqrt{\frac{3}{4} }  T$

Explanation:

g' = g+ g/3 = 4g/3

T ∝ $\sqrt{g}$

T' = $\sqrt{\frac{3}{4} }  T$