Question

The time period of a simple pendulum is 4.0 second and length of the simple pendulum is 2.50 meter. Find the percentage error in acceleration due to gravity

Answer 1

Hello!

Given,L=200cm=2m,T=40/20=2second,

Now ,

g=4 pi square L/T square

=4× 3.14×3.14×2/2×2

=19.72m/s square

And the perchantage error= 19.72-9.8=9.92(Answer)

Thanks!

Answer 2

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