Question

The time period of a simple pendulum is The =k^l/G the percentage error in length and acceleration due to gravity are 2%and4% then the percentage error in time period is

Answer 1

Answer:

Explanation:

Time period, T=2π  

g

l

​  

 

​  

 

or g=  

T  

2

 

4π  

2

l

​  

 

The maximum percentage error  

g

Δg

​  

=  

l

Δl

​  

+2  

∣

∣

∣

∣

∣

​  

 

T

ΔT

​  

 

∣

∣

∣

∣

∣

​  

 

where  

l

Δl

​  

=2% and  

T

ΔT

​  

=3%  

g

Δg

​  

=2%+2×3%  

       =2%+6%=8%