The time period of a simple pendulum of length 80 cm on the earth is
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Hello Mate, here is the your solution ÷
As,
![t \: = 2 \times \pi \sqrt{(.8 \div 9.8)} t \: = 2 \times \pi \sqrt{(.8 \div 9.8)}](https://tex.z-dn.net/?f=t+%5C%3A++%3D+2+%5Ctimes+%5Cpi+%5Csqrt%7B%28.8+%5Cdiv+9.8%29%7D+)
Answer - 1.79 s
As,
Answer - 1.79 s
Answered by
2
Given :
Length of pendulum , L = 80 cm = 0.8 m .
To Find :
The time period of a simple pendulum .
Solution :
The time period of a simple pendulum of length L is given by :
Here , g is acceleration due to gravity i.e , .
So ,
Hence , this is the required solution .
Learn More :
Time period
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