Question

The time period of a simple pendulum of length L as measured in an elevator descending with acceleration is

Answer 1

Answer:

the simple pendulum is descending with accleraion g/3. so there will be a pseudo force on the pendulum upwards of mg/3 . so the net acceleration is 2g/3. so, the time period is T = 2*pi √(l/anet) = 2*pi √(3l/2g).