Physics, asked by gayathrizz0210, 11 months ago

The time period of a soap bubble is T which depends on pressure P, density D and surface tension S. then relation for T is: a) T∝Pds b) T∝Pd⁻³/₂d¹/₂s c) T∝Pd⁻²s³/₂ d) T∝Pd²s¹/₃

Answers

Answered by pritam4537
26

Answer:

The time period of a soap bubble is T which depends on pressure P, density D and surface tension S. then relation for T is: a) T∝Pds b) ...

Answered by ansiyamundol2
0

Answer:

The correct answer is Option B : P^{\frac{-3}{2}} d^{\frac{1}{2}} S

Explanation:

Firstly, we take the dimensions of the given data :

T=[T]

P =[M^1L^{-1}T^{-2}]

d=[M^1L^{-3}]

S=[M^1T^{-2}]

To find the relation for time period T :

Time periods ∝ Pressure

Time periods ∝ Density

Time periods ∝ Surface tension

T ∝ P^ad^bS^c

LHS and RHS must be dimensionally equal.

[T^1]=[M^1L^{-1}T^{-2}][M^1L^{-3}][M^1T^{-2}]

M ⇒ 0=a+b+c

L ⇒ 0=-a-3b     --- This can be written as a=-3b

T ⇒ 1=-2a-2c

L ⇒ 0=-3b+b+c

0=-2b+c\\c=2b

T ⇒ 1=-2(-3b)-2(2b)\\

1=6b-4b\\b=\frac{1}{2} \\

From the value of b, we get :

a=\frac{-3}{2}\\ c=1

T ∝ P^ad^bS^c

T ∝ P^{\frac{-3}{2}} d^{\frac{1}{2}} S^1

Hence we get the relation.

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