The time period of an artificial satellite in a circular orbit of radius R is 2 days
and its orbital velocity is Vo. If time period of another satellite in a circular orbit
is 16 days then:
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Explanation:
According to the Kepler's third law T
2
∝R
3
∴
T
2
T
1
=(
R
2
R
1
3/2
)
or R
2
=(R
1
)(
T
1
T
2
)
3/2
=(R
1
)(
2
16
)
2/3
=4R
1
=4R (given R
1
=R) ....(i)
Orbital velocity, v
o
=
R
GM
∴
v
o1
v
o2
=
R
2
R
1
=
4R
1
R
1
=
2
1
....(using (i))
or v
o2
=
2
1
v
o1
=
2
1
v
o
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