the time period of earth is taken as T and its distance from sun as R .what will be the distance of a certain planet from sun whoes time period is 64 times that of earth
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T^2 = k. R^3 .. 1.
T'2 = k. R^3
= (64T)^2 = k. R'^3 .. 2.
Divide 2. By 1.
= (64T)^2 / T^2 = k. R'^3 / k. R^3
= 64*64 T^2 / T^2 = R'^3 / R^3
= 64*64 = R'^3 / R^3
= under cube root 64*64 = R' / R
= 4*4 = R'/ R
= 16= R'/ R
= 16R = R'.
Hope it's helpful to u.
T'2 = k. R^3
= (64T)^2 = k. R'^3 .. 2.
Divide 2. By 1.
= (64T)^2 / T^2 = k. R'^3 / k. R^3
= 64*64 T^2 / T^2 = R'^3 / R^3
= 64*64 = R'^3 / R^3
= under cube root 64*64 = R' / R
= 4*4 = R'/ R
= 16= R'/ R
= 16R = R'.
Hope it's helpful to u.
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