The time period of oscillation of a simple pendulam having lenth L and mass of the bob m is given as T. If the lenth of the pendulam is increased to 4L and the mass of the bob is increased 2m, then which one of the following is the new time period of oscillation ?
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Answer:
T=2π √l/√g
Explanation:
T=2π√4l/√g
mass of Bob has no effect here
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