Physics, asked by Shefali6991, 9 months ago

The time period of oscillation of a simple pendulum is given by T=2pisqrt(l//g) The length of the pendulum is measured as 1=10+-0.1 cm and the time period as T=0.5+-0.02s. Determine percentage error in te value of g.

Answers

Answered by eqbaltausif0
1

Answer:

Explanation:

The percentage error in the measurement of time period of simple pendulum is 3%. Hence, The percentage error in the measurement of time period of simple pendulum is 3%.

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