Question

The time period of oscillation of a simple pendulum is given by T=2pisqrt(l//g) The length of the pendulum is measured as 1=10+-0.1 cm and the time period as T=0.5+-0.02s. Determine percentage error in te value of g.

Answer 1

Answer:

Explanation:

The percentage error in the measurement of time period of simple pendulum is 3%. Hence, The percentage error in the measurement of time period of simple pendulum is 3%.