Chemistry, asked by sridevibobba04, 7 months ago

The time period of revolution in the 3rd orbit of Li2+ ion is​

Answers

Answered by vanigayatri2007
1

Answer:

The time period of revolution in the 3rd orbit of Li2+ ion is x sec

Answered by SumitmuneshwarEXPERT
0

Answer:Revolution per sec = kz^2/n^3

z=3 , n=3

=6.66 ×10^15×9/27

=6.66 ×10^15×1/3

=2.22×10^15

hope it helps

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