The time period of revolution in the 3rd orbit of Li2+ ion is
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Answer:
The time period of revolution in the 3rd orbit of Li2+ ion is x sec
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Answer:Revolution per sec = kz^2/n^3
z=3 , n=3
=6.66 ×10^15×9/27
=6.66 ×10^15×1/3
=2.22×10^15
hope it helps
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