The time period of satellite at a height R(from surface of earth) is T. The time period in an orbit of radius 3R will be (R: Radius of earth)
(A) 3√3T
(B)√3/2T
(C)3/2√3/2T
(D)3/2T
Answers
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Answer:
A) 3√3T
Explanation:
Use Kepler's third law and consider distance as radius for simplicity:
T2^2/T1^2 = r2^3/r1^3
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Sangwan420:
is it confirm
??
Yes
no .. it's a wrong one
the answer is 3/2√3/2
Sorry, here r1=R+R=2R, my answer is wrong
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