The time period of the simple pendulum called second pendulum is 2 so. Calculate the length, angular frequency & frequency of the pendulum?
Answers
Answered by
7
T =2π√(L/g)
put T = 2 sec and g = 10 m/s²
2 = 2π√(L/10)
4 =4π²L/10
40 = 4π²L
L = 10/π² meter
angular frequency = 2π/T
=2π/2 = π cycle/sec
frequency = 1/T = 1/2 Hz
put T = 2 sec and g = 10 m/s²
2 = 2π√(L/10)
4 =4π²L/10
40 = 4π²L
L = 10/π² meter
angular frequency = 2π/T
=2π/2 = π cycle/sec
frequency = 1/T = 1/2 Hz
Asm12:
thankuuu
Similar questions