Question

The time period of two Pendulums is 2sec and 3sec. Find ratio of their length

Answer 1

Answer:

2:3

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Answer 2

Answer:

Explanation:T=2π√(L/g)

Let T₁ = 2s , L₁ be the length in initial case.

ie., 2= 2π√(L₁/g)

∴L₁ = 4g/4π²

T₂ = 3s , L₂ be the length.

ie., 3 = 2π√(L₂/g)

∴L₂ = 9g/4π²

∴ Ratio = L₁/L₂ = 4/9