The time period of two simple pendulum at a place are in 2:1.What will be the ratio of their length??? Please tommorow is my test??
Answers
Answered by
0
we know, t=2π√l/g
therefore, (t1/t2)^2=l1/l2
since t1/t2=2:1,
therefore, (2/1)^2= l1/l2
or, l1:l2=4:1
therefore, when the ratio of the time period is 2:1, the ratio of length will be 4:1.
therefore, (t1/t2)^2=l1/l2
since t1/t2=2:1,
therefore, (2/1)^2= l1/l2
or, l1:l2=4:1
therefore, when the ratio of the time period is 2:1, the ratio of length will be 4:1.
Answered by
2
Hey! Here is ur answer...
T=2π√[l/g]
We can see that, T² is directly proportional to length....
So, L1/L2=(T1/T2)²
T1/T2 is 2:1
So, L1/L2 = 4:1
Hope it will help u... Plz mark it as brainliest... :)
T=2π√[l/g]
We can see that, T² is directly proportional to length....
So, L1/L2=(T1/T2)²
T1/T2 is 2:1
So, L1/L2 = 4:1
Hope it will help u... Plz mark it as brainliest... :)
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