Question

The time period of two simple pendulums A and B are 4 s and 12 s respectively. Compare their frequencies.​

Answer 1

Explanation:

I think the answer is 4:12.

Hope you understand

Answer 2

Answer:

Frequency of A = 3 × Frequency of B

Explanation:

• Time period: Time period means time taken to complete one oscillation for a pendulum. Time period is indicated by 'T'. The SI unit of time period is second.
• Time period of pendulum A = Ta = 4s

        Time period of pendulum B = Tb = 12s

• Frequency: How many times a pendulum oscillates in one second is expressed by its frequency.

       Frequency = $\frac{1}{time period}$ . Unit of frequency is Hz.

• Comparison of frequency: Frequency of A = $\frac{1}{T_a}$ = $\frac{1}{4}$ = 0.25 Hz.

                                                      Frequency of B = $\frac{1}{T_b}$ = $\frac{1}{12}$ = 0.08 Hz.

        By taking ratio = $\frac{Frequency of A}{Frequency of B}$ = 3

                                    Frequency of A = 3 × Frequency of B

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