Physics, asked by Akumansi, 8 months ago

The time
period T of
a small drop of
liquid (due to surface tension depend on
density p, radius r & and surface tensions s

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Answered by yash404070
3

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Time period of an oscillating drop of radius r, density ρ and surface tension S is t=K√ρr3S. Check the correctness of this relation. As dimensions on both sides are same, the relation is correct.

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