Question

The time required to coat a metal surface of 80cm2 with 5×10−3cm thick layer of silver (density 10.5gcm−3) with the passage of 3A current through a silver nitrate solution is

Answer 1

I think so question is not correct

Answer 2

Explanation:

volume=surface area ×thickness=5×10^-3×80=0.04cm^3

mass=vol×density =0.04×10.5=0.42g

we know that W=Eit/F

0.42=108×3×t/96500

t=0.42×96500/108×3

calculating we get t=125.9 sec