Question

The time T of oscillation of a simple pendulum of length L is governed by T=√L /g where g is constant.The percentage by which the length be changed in order correct an error of loss equal to 2 minutes of time per day is​

Answer 1

Answer:

Explanation:

T = 2π√1/g

→AI/I x 100 = 1 (Given) Here we are

using Percentage error formula

dy/y × 100

(OR) dx/x x 100 → dl/l x 100 = 1

→ T = 2π√1/g

→ T = 2π(l/g)¹/²

Now, Apply Log on Both sides

logT = log2n(l/g)¹/²

-> logT - log2n + log(l/g)¹/²

logT = log2n + 1/2log(l/g)

→logТ = log2 + 1/2[log 1 - log g]

log T = log 2n + 1/2log I - 1/2log g

→ 1/T x dt = 0 + 1/2 x 1/1-1/2 × (0)

→ 1/Tx dt = 1/2 dl/l

→ dT/T = 1/2 dl/l

→ dT/T x 100 = 1/2 dl/lx 100 {Apply

Percentage error formula }

→ dT/T x 100 = 1/2 % ANSWER}