Question

The time taken by 4 men to complete a job is double the time taken by 5 children to complete the same job. each man is twice as fast as woman. how long will 12 men, 10 children & 8 women take to complete a job, given that a child would finish the job in 20 days

Answer 1

So like this the unitary method question is solved

Answer 2

Answer:

1 days

Step-by-step explanation:

Since, the time taken by 4 men to complete a job is double the time taken by 5 children to complete the same job.

Since, it is being given that;

1 child would finish the job in 20 days.

So, 5  child will complete it in 20/5 =4 days.

So, work done by 1 child in 1 day would be 1/20.

Since, it is being given that time by 4 men = 2 times time taken by 5 child.

So, work done by 4 men =  $2 \times 4$  

                                           = 8 days.

So, work done by 1 men would be $8 \times 4$ = 32 days.

So, work done by 1 man in 1 day would be 1/32.

Since, each man is twice as fast as woman.

So, the same work done by 1 woman would be $32 \times 2 = 64$ days.

So, work done by 1 woman in 1 day would be 1/64.

So, total work done by all of them in one day would be:

1/20 + 1/32 /1/64 =

total work by 10 children would be 10/20 =1/2

total work by 12 men would be 12/32 = 3/8

total work by 8 women would be 8/64 = 1/8

total work by 10 children , 12 men,  8 women would be = 1/2 + 3/8 +1/8

= 8/8

= 1

So, total time would be 1 days.