Math, asked by YuvrajShresth, 20 days ago

The time taken by a 240m log train, traveling at a speed of 72km/hr to cross a pole is what?​

Answers

Answered by laxmi029193
0

Answer:

Given:

Speed of the train = 72 km/h

Length of the train = 240 m

Time to cross a tunnel = 1 minute

Concept used:

Distance = Speed × Time

km/h × 5/18 = m/sec

1 minute = 60 sec

Calculation:

Speed of the train = 72 km/h

⇒ 72 × 5/18 = 20 m/sec

Time to cross the tunnel = 60 sec

Let the length of the tunnel be L.

(240 + L)/20 = 60

⇒ (240 + L) = 60 × 20

⇒ 240 + L = 1200

⇒ L = 1200 – 240

⇒ L = 960

∴ The length of the tunnel is 960 m.

Answered by aftabahemad
0

In context to question asked,

We have to determine the time taken by 240 m long train to cross the pole, if it is running with a speed of 72 Kmph.

So, for determining the time,

We will convert speed into m/sec.

So, we will get the speed in m/sec/ as - 72 \times \frac{5}{18} = 20\:m/sec.

So, as the speed of train is 20 m/sec.

So, when it cover the pole,

Then the expression for time period will be,

Time = \frac{Length\:of\:Train}{Speed\:of\:Train}

Hence, putting the value given in question in above formula,

We will get,

Time = \frac{240}{20} = 12\:sec.

Hence, train will take 12 seconds to cross the pole.

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