Question

The time taken by a train to slow down from 80 km/h to 20 km/h with a uniform deceleration of 2 ms-2 is

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Answer 1

Answer:

As,v=u+at

20= 80+(-2)×t

80-2t=20

-2t=20-80

-2t=-60

t=-60/-2

t=30 seconds.

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Answer 2

Answer:

v=u+at

5.55=22.2-2*t

2t=16.7

t=16.7/2

=8.4 sec