Question

the time taken by a train to slow down from 80 km/s to 20 km/s with a uniform deceleration of 2n/s^2 is​

Answer 1

Answer:

Time taken by train to slow down is approx 8.33 second

Explanation:

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#Ayush.

Answer 2

Answer:

time = final velocity - initial velocity / deceleration

80km/hr -> m/s

80*5/18 = 400 / 18

= 22.2m/s

20km/hr -> m/s

20*5/18 = 100 / 18

= 5.5m/s

t = 5.5m/s - 22.2 m/s / - 2m/s^2

t = -16.7m/s/ -2m/s^2

t = 8.35 s

hope May it be helpful