the time taken by a train to slow down from 80km/h with a uniform deceleration of 2 m/so
Answers
Answered by
2
Answer:
v=u+at
0=80-2t
80=2t
40=t
time taken is 40 secs
Answered by
1
Answer:
time taken to slow down is 11.11 hours
Explanation:
a=2m/s=2×3600/1000
a=7.2km/hr
u=80km/hr
v=0
using Newton's 1st equation of motion
v=u+at
0=80-7.2t
t=80/7.2
t=11.11hr
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