Question

The time taken by an electron to complete one rotation about its nucleus
is 0.5x10-18 seconds. Convert it into minutes, hours and microseconds.​

Answer 1

-

Time taken for an electron to complete one revolution in Bohr orbit of hydrogen atom is : t=distance/velocity

Distance of Bohr orbit = circumference of Bohr orbit = 2πr

t=

v

2πr

Since mvr=

2π

nh

v=

2πmr

nh

Thus, t=2πr×

nh

2πmr

t=

nh

4π

2

mr

2

Hope that this will helpful to u...

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Answer 2

The correct answer is 8.333 x $10^{-21}$ minutes, 1.388 x $10^{-22}$ Hours and  $0.5*10^{-12}$ microseconds.

Given: Time taken by an electron to complete one rotation about its nucleus is 0.5x10-18 seconds.

To Find: Convert it into minutes, hours and microseconds.​

Solution:

60 second = 1 Minute

$\frac{0.5*10^{-18} }{60}$

= 0.08333 x $10^{-19}$

= 8.333 x $10^{-21}$ minutes.

60 Minutes = 1 Hour

= $\frac{8.333*10^{-21} }{60}$

= 1.388 x $10^{-22}$ Hours

1 microsecond = $10^{-6}$ seconds

= $\frac{0.5*10^{-18} }{10^{-6} }$

= $0.5*10^{-12}$ microseconds

Hence, the answers are 8.333 x $10^{-21}$ minutes, 1.388 x $10^{-22}$ Hours and  $0.5*10^{-12}$ microseconds.

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