Math, asked by GaneshBase, 10 months ago

the time taken by Ram to cover 150 kilometre was 2.5 hours more than the time taken in the return journey is returned at a speed of 10 kilometre per hour more than the speed of going what was the speed per hr in each direction
(step by step explanation need )​

Answers

Answered by rishavkumar9507
1

Answer:

he goes at a speed of 20km per hour and came back at a speed of 30km per hour

Answered by Anonymous
8

The Speed at the time of going is 20 km/hr and while returning is 30 km/hr.

Given:

  • Distance = 150 km
  • 2.5 hours more than the time taken in the return journey.
  • Returned at a speed of 10 kilometre per hour more than the speed of going.

Explanation:

Let the speed at the time of going be x km/hr

again,

Speed at the time of returning be (x + 10) km/hr

According to Question,

 \\ \colon\implies{\sf{ \dfrac{150}{x} - \dfrac{150}{x+10} = 2.5 }} \\ \\ \\ \colon\implies{\sf{ \left( \dfrac{x+10-x}{x(x+10)} \right) \times 150 = 2.5 }} \\ \\ \\ \colon\implies{\sf{ \left( \dfrac{x+10-x}{x(x+10)} \right) \times 150 = \dfrac{5}{2} }} \\ \\ \\ \colon\implies{\sf{ 10 \times 150 \times 2 = 5(x^2 + 10x ) }} \\ \\ \\ \colon\implies{\sf{ x^2 + 10x - 600 = 0 }} \\

  • x = 20 km/hr
  • x = 30 km/hr

Hence,

  • The Speed at the time of going is 20 km/hr and while returning is 30 km/hr.

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